习题参考答案
Section titled “习题参考答案”-
hatμ₃ 有效性最差. 2. 不是. 3. 略.4(1)/(2(n - 1)) . 5. 1/2 (x_((1)) + x_((n))) 较有效.
-
4/3x_((3)) 较有效. 7. a=fracn₁n₁+n₂, b=fracn₂n₁+n₂ . 8. 略. 9. aᵢ=frac1σᵢ²/∑ⱼ=1ⁿfrac1σⱼ², i=1,2,…,n.
-
略. 11. C₁ = √((nπ)/(2(n - 1))), C₂ = (√(π))/(2) .
习题 6.2
Section titled “习题 6.2”-
114 3.75, 96.056 2. 2. 2.68. 3. (1) 2overlinex ; (2) frac2overlinex .
-
(1) 3overlinex ; (2) frac1 - 2overlinexoverlinex - 1 ; (3) (fracoverlinex1 - overlinex)² ; (4) hatθ = s, hatμ = overlinex - s.
-
uₖ / n 6. (1) (ab)/(c) ; (2) (ab)/(c) - a - b + c . 7. hatm = [fracoverlinex²overlinex - sₙ²], hatp = 1 - fracsₙ²overlinex .
习题 6.3
Section titled “习题 6.3”-
(1) (1/n ∑ᵢ=1ⁿ ln xᵢ)⁻2 ; (2) (1/n ∑ᵢ=1ⁿ ln xᵢ - ln c)⁻1 .
-
(1) x_((1)) ; (2) hatμ = x_((1)), hatθ = overlinex - x_((1)) ; (3) fracx_((n))k + 1 .
-
(1) 1/n ∑ᵢ=1ⁿ |xᵢ| ; (2) 可取 (x_((n)) - 1/2, x_((1)) + 1/2) 中的任意值; (3) hatθ₁ = x_((1)), hatθ₂ = x_((n)) .
-
0.499. 5. frac2(overlinex - 1)overlinex . 6. 28.305 3. 7. (1) 略; (2) 不是无偏估计,是相合估计.
8.(1)是相合估计,不是无偏估计;(2)是相合估计,是无偏估计.
-
-
- 略.
-
习题 6.4
Section titled “习题 6.4”1—5. 略 6. (1) -1/n ∑ᵢ=1ⁿ ln xᵢ ; (2) -1/n ∑ᵢ=1ⁿ ln xᵢ . 7. (1)/(θ²) . 8. (1)/(θ²) . 9. (2)/(θ²(1-θ)) .
-
略. 11. fracmbarx + 1/2nbarym + 1/2n, (1)/(m + n - 1)(∑ᵢ=1^(m) xᵢ² + 1/2 ∑ᵢ=1ⁿ yᵢ² - frac(mbarx + 1/2nbary)²m + 1/2n) . 12. 略.
-
(1) θ³ ; (2) g(θ) = a√(θ) + b ( a > 0, b 任意).
-
(1) 1/2 + frac∑ᵢ=1ⁿ xᵢ2 ∑ᵢ=1ⁿ xᵢ² ; (2) overlinex + 1/2 ; (3) (2θ(1 - θ))/(n) . 15. 略.
习题 6.5
Section titled “习题 6.5”-
P(λ = 1.5 | x = 3) = 0.3899, P(λ = 1.8 | x = 3) = 0.6101. 2. U(11.1, 11.7) .
-
(1) Be(n + 1, ∑ᵢ=1ⁿ xᵢ + 1) ; (2) 0.25. 4—5. 略
-
(1) π(θ | x₁, x₂, …, xₙ) = frac2n-1θ²n(x_((n))⁻2n+1-1) ; (2) π(θ | x₁, x₂, …, xₙ) = frac2n-3θ²n-2(x_((n))⁻2n+3-1) .
-
fracn + αλ - ∑ᵢ=1ⁿ ln xᵢ . 8. (1) 略; (2) frac(n + β) max {x_((n)), θ₀}n + β - 1 . 9. Ga(0.0004, 2) .
-
略 11. π (θ | x₁, x₂, x₃) = 6 × 8⁶ θ⁻7, θ > 8. 12—13. 略
-
Be(5,297).
习题 6.6
Section titled “习题 6.6”-
[1.916 8,2.583 2]. 2. ((3.92σ)/(k))² .
-
(1) [-0.9800, 0.9800] ; (2) [0.6188, 4.3929] .
-
(1) [0.148 7, 0.421 5]; (2) [56.073 9, 56.566 1].
-
(1) [432.306 4,482.693 6]; (2) [438.905 8,476.094 2];
(3) [24.223 9,64.137 8]. 6. [0.074 2,0.200 8]. 7. 略.
- [11.039 2, 12.999 2]. 9. (1) [-0.093 9, 12.093 9]; (2) [-0.206 3, 12.206 3];
(3) [-0.3288, 12.3288] ; (4) [0.3359, 4.0973] .
-
(1) [0.062 0, 1.007 5]; (2) [-0.285 5, 0.325 5]. 11. (fracχ_((α)/(2))²(2n)2noverlinex, fracχ₁ - (α)/(2)²(2n)2noverlinex) .
-
[36.76, 113.64], 98.04, 40.82. 13. [m₀.5 - (π)/(2√(n)) u₁ - (α)/(2), m₀.5 + (π)/(2√(n)) u₁ - (α)/(2)] .
-
(64u₁² - (α)/(2))/(L²) . 15. 略. 16. [fracx_((n)) + x_((1))2 -frac1 - α¹ / n2,fracx_((n)) + x_((1))2 +frac1 - α¹ / n2] .
-
(1) [fracx_((n)) - x_((1))Be₁ - α / 2(n - 1,2),fracx_((n)) - x_((1))Be_(α / 2)(n - 1,2)] ;
(2) [fracx_((n)) + x_((1))2 -fracc(x_((n)) - x_((1)))2,fracx_((n)) + x_((1))2 +fracc(x_((n)) - x_((1)))2],其中 c = ((1)/(α))^((1)/(n - 1)) - 1.
-
[fracx_((m))y_((n))((m + n)/(2m)α)¹/n,fracx_((m))y_((n))((m + n)/(2n)α)⁻1/m].
-
(1) 略; (2) [x_((1)) + (ln α)/(n), x_((1))] .